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3 years ago

5+13/18=can y’all please help me this is hard

Mathematics

2 answers:

eduard3 years ago

8 0

Answer: 1

Step-by-step explanation:

5+13/18

18/18

patriot [66]3 years ago

7 0

Answer:

The answer is 5 13/18

Step-by-step explanation:

-Convert any mixed numbers to fractions.

-Then your initial equation becomes:

-5/1 + 13/18

-Applying the fractions formula for addition,

=(5×18) + (13×1) 1×18

=90 + 13/18

=103/18

Simplify 103/18, and you get:

5 13/18

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Use the rules of exponents to evaluate or simplify.write without negative exponents. 1/4^-2=?

Talja [164]

9514 1404 393

Answer:

4² = 16

Step-by-step explanation:

The applicable rule of exponents is ...

1/a^-b = a^b

So, ...

$\dfrac{1}{4^{-2}}=\boxed{4^2 = 16}$

_____

<em>Additional comment</em>

If you were to evaluate this using the Order of Operations, you would evaluate the exponent first:

1/4^-2 = 1/(1/16)

Then, you would do the division.

1/(1/16) = 16

We sometimes find it convenient to manipulate exponential terms to the form with the smallest positive exponents before we begin the evaluation.

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2 years ago

My friend needs help again

ICE Princess25 [194]

Answer:

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3 years ago

Anyone, please help me please answer my question because I have to pass this tomorrow morning:(

Wittaler [7]

Step-by-step explanation:

If you need help with how I got my answer, you can ask me.

$\frac{2yx {}^{ - 4} }{(x {}^{ - 4}y {}^{4}) {}^{3} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2yx {}^{ - 4} }{x {}^{ - 12}y {}^{12} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2y x {}^{ - 4} }{2x {}^{ - 13} y {}^{ - 9} }$

$= x {}^{9} y {}^{ - 8}$

$= \frac{x {}^{9} }{y {}^{8} }$

12.

$( \frac{2u {}^{ 4} }{ - u {}^{2}v {}^{ - 1} \times 2uv {}^{ - 4} } ) {}^{ - 1}$

$( \frac{2u {}^{4} \times 1 }{ - 2 {u}^{3}v {}^{ - 5} } ) {}^{ - 1}$

$( - u v {}^{ 5} ) {}^{ - 1}$

$= - u {}^{ - 1} v {}^{ - 5} = - \frac{ 1}{uv {}^{5} }$

13.

$- \frac{2m {}^{4}n {}^{ - 1} }{( - m {}^{2}n {}^{ - 2}) {}^{ - 1} \times - nm {}^{ - 3} }$

$- \frac{2m {}^{4}n {}^{ - 1} }{ - m {}^{ - 2} n {}^{2} \times - nm {}^{ - 3} }$

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$= - \frac{2m {}^{9} }{n {}^{4} }$

14.

$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{2} y {}^{ - 3} \times yx {}^{0} } ) {}^{3}$

$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{ - 2}y {}^{ - 2} } ) {}^{3}$

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$- \frac{x {}^{15} }{ {y}^{6} }$

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$- \frac{yx {}^{4} \times - {y}^{3} z { }^{ - 4} }{(z {y}^{2} ) {}^{4} }$

$- \frac{ - y {}^{4} x {}^{4} z {}^{ - 4} }{ {z}^{4} y {}^{8} } = - y {}^{4} x {}^{4} z {}^{ - 8} = - \frac{(xy) {}^{4} }{ {z}^{8} }$

16.

$\frac{h {}^{7}j {k}^{4} }{4h {}^{4} } = \frac{1}{4} h {}^{3} = \frac{h {}^{3} jk {}^{4} }{4}$

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2 years ago

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shusha [124]

Answer:

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Answer:

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Step-by-step explanation:

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2 years ago

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