Answer:
mn
Step-by-step explanation:
Yo has to factor since we assume that
if you have xy=0, x and y=0
7n^2-48n+36=0
trial and error
(7n-6)(n-6)=0
set each to zero
7n-6=0
add 6
7n=6
divide 7
n=6/7
n-6=0
add 6
n=6
n=6/7 or 6
Answer:
b. 
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Functions
- Function Notation
- Exponential Rule [Rewrite]:
- Exponential Rule [Root Rewrite]:
<u>
</u>
<u>Calculus</u>
Derivatives
Derivative Notation
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Chain Rule]: ![\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<u>Step 2: Differentiate</u>
- Rewrite function [Exponential Rule - Root Rewrite]:
![\displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20H%28x%29%20%3D%20%5BF%28x%29%5D%5E%5Cbigg%7B%5Cfrac%7B1%7D%7B3%7D%7D)
- Chain Rule:
![\displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20H%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cbigg%5B%20%5BF%28x%29%5D%5E%5Cbigg%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%5Cbigg%5D%20%5Ccdot%20%5Cfrac%7Bd%7D%7Bdx%7D%5BF%28x%29%5D)
- Basic Power Rule:
![\displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20H%27%28x%29%20%3D%20%5Cfrac%7B1%7D%7B3%7D%5BF%28x%29%5D%5E%5Cbigg%7B%5Cfrac%7B1%7D%7B3%7D%20-%201%7D%20%5Ccdot%20F%27%28x%29)
- Simplify:
![\displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20H%27%28x%29%20%3D%20%5Cfrac%7BF%27%28x%29%7D%7B3%7D%5BF%28x%29%5D%5E%5Cbigg%7B%5Cfrac%7B-2%7D%7B3%7D%7D)
- Rewrite [Exponential Rule - Rewrite]:
![\displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20H%27%28x%29%20%3D%20%5Cfrac%7BF%27%28x%29%7D%7B3%5BF%28x%29%5D%5E%5Cbigg%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D)
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em> [Derivative]:
![\displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20H%27%285%29%20%3D%20%5Cfrac%7BF%27%285%29%7D%7B3%5BF%285%29%5D%5E%5Cbigg%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D)
- Substitute in function values:

- Exponents:

- Multiply:

- Simplify:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
An exponential parent function is the option C. f(x)=
, from the given options.
What do you mean by exponential parent function?
The formula for their parent function is y =
, where b is any non zero constant. Below is a graph of the parent function, y =
, which demonstrates that it will never equal 0. And at y = 1 when x = 0, y crosses the y-axis.
According to options in the given question,
We have the option below in the given question:
A. f(x) = 2^x – 3 
B. f(x) = 2^x + 2 
C. f(x) = 2^x 
D. f(x) = 2^x + 1/3
We know from the above definition that the option C. is the right answer to the given question.
Therefore, the exponential parent function is f(x)=
.
To learn more about exponential parent function, visit:
brainly.com/question/24210615?referrer=searchResults
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