Answer:
a^2 +b^2=c^2
Given vertices of the triangle are A(4,4),B(3,5) and C(−1,−1)
We know that slope of line passing through the points (x 1,y 1) and (x 2,y 2
) is given by m= x 2−x 1
y
2
−y
1
,x
2
=x
1
Slope of AB i.e.m
1
=
3−4
5−4
=−1
Slope of BC i.e.m
2
=
−1−3
−1−5
=
−4
−6
=
2
3
Slope of CA i.e. m
3
=
4+1
4+1
=
5
5
=1
Clearly, m
1
m
3
=−1
⇒ line segments AB and CA are perpendicular to each other i.e; the given triangle is right angled at A(4,4).
Thus the points (4,4),(3,5) and (1,1) are the vertices of a right angled triangle.
Step-by-step explanation:
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Answer:
The radius is: 
Step-by-step explanation:
The equation of a circle in center-radius form is:
Where the center is at the point (h, k) and the radius is "r".
So, given the equation of the circle:
You can identify that:
Then, solving for "r", you get that the radius of this circle is:
With cross multiplication you can find that they are the same. In both equations, x would be 100.
