Answer:
Step-by-step explanation:
3*7*10*10*10*10*10*10*10
(5+2=7)(since is multiplication you add)
21*
=B
<u>2*10*10*10*10*10</u>
4*10*10
(5-2=3)(since is division you subtract)
0.5*
=c
It’s an irrational number (can’t be expressed as a fraction with two integers).
Answer:
yes
Step-by-step explanation:
There are several ways to go at this.
My first choice is to use a graphing calculator. It shows the function has a zero at x=5, so x-5 is a factor.
Another good choice is to use synthetic division (2nd attachment). If the remainder is zero, then x-5 is a factor. It is and it is.
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You can also evaluate the function at x=5. The remainder theorem tells you that if the value is zero, then x-5 is a factor. Evaluating the polynomial written in Horner form is a lot like synthetic division.
(((x -4)x -15)x +58)x -40 for x=5 is ... (-10·5 +58)5 -40 = 40-40 = 0
The value of h(5) is zero, so x-5 is a factor of h(x).
Answer:
a. 3
Step-by-step explanation:
We can get to know if a number is divisible by 3 if after adding all the digits of that number we get a number which is completely divisible by 3 or we can say the number appears in the table of 3.
For example: In the given number if we will add all the digits the we will get 21 and we all know that 21 is divisible by 3.
10,534,341 = 1 + 0 + 5 + 3 + 4 + 3 + 4 + 1 = 21
21 = 21/3 = 7
Other options are incorrect.
Divisibility rule for 2 : A number is said to be divisible by 2 if it's ones place ends in 0, 2, 4, 6 or 8 i.e. an even number. The given number does not satisfy this condition because it ends in 1 which is an odd number.
Divisibility rule for 9 : A number is said to be divisible by 9 if after adding all the digits of that number we get a number which is completely divisible by 9. Since the sum total of the given number is 21 which is not completely divisible by 9 we can easily infer that 9 is not the answer for this question.