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Anton [14]
3 years ago
13

What is the area of the poster board that she has left

Mathematics
1 answer:
steposvetlana [31]3 years ago
5 0
Find the area of the parallelogram, find the area of the triangle, then subtract the triangle's area from the area of the parallelogram.

Area of Parallelogram:
A= base * height
A= 20 in * 10 in
A= 200 in^2

Area of Triangle:
A= 1/2 base * height
A= 1/2 (10 in)(9 in)
A= 1/2 (90)
A= 45 in ^2

Area of Poster Left:
subtract the difference
A= Parallelogram Area - Triangle Area
A= 200 in^2 - 45 in^2
A= 155 in^2

ANSWER: 155 in^2 is the area of the poster board she has left.

Hope this helps! :)
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jim can plant 8 trees in 18 hours. kinda can plant 8 trees in 9 hours. how long will it take him and linda working together to p
algol [13]

Answer:

Jack plants 20 more trees than Jim.

4 0
3 years ago
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The present value of an ordinary annuity of​ $350 each year for five​ years, assuming an opportunity cost of 4​ percent, is​ ___
liubo4ka [24]
We can calculate it by PVOA table.
PVOA means present value of an ordinary annuity.
PMT = $350
PMT means recurring payment.
time = 5 years and interest rate is 4%
So n = 5 and i = 4%
So we can calculate PVOA as

PVOA = PMT times (PVOA factor for n = 5 and i = 4%)
             = 350 * (4.452) (PVOA factor PVOA table)
             = 1558.2
So present value is $1558.2
4 0
3 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
Find the scale factor
7nadin3 [17]

Answer:

X = 10 or scale factor is 2.5

Step-by-step explanation:

first look at the scale factor going from 4 to 10, to get from 4 to 10 you would need to multiply 4 by 2.5. Since this problem doesnt give us the smaller scale factor first we need to divide 25 by 2.5 which equals 10.

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3 years ago
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HELP ME PLSSSS I BEG UUUU
Soloha48 [4]
1 and 3 would be correct
7 0
2 years ago
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