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hoa [83]
3 years ago
15

Martha estimated there were 96 marbles in a jar for a contest. The actual number of marbles in the jar was 118. What was the per

cent error of Martha's estimation?
Mathematics
1 answer:
matrenka [14]3 years ago
3 0
To find percent error, you subtract the actual number from your estimate, take the absolute value, and divide by the actual number.

l 96 - 118 l
l -22 l
l 22 l
l 22 l / 118
0.19%  (this was rounded)

Hope this helps!
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20 POINTS!!
svet-max [94.6K]

9514 1404 393

Answer:

  P = 3x +32

Step-by-step explanation:

If we assume the short vertical edge at top center is 10 yards, as it was in two previous problems with this geometry, then we can find the area of the present parking lot as ...

  (x-2)(3x) + x(3x -10) +2x(40) = 6x^2 +64x

where the left vertical rectangle is 3x high and x-2 wide; the center area between vertical rectangles is (2x-2)-(x-2) = x wide and (3x-10) high; and the right vertical rectangle is (x-2 +3x)-(2x-2) = 2x wide and 40 high.

As we said, the right vertical rectangle is 2x wide, so the area that has P as one of its dimensions is ...

  A = LW = P(2x)

We want this to be the same as the existing area, so ...

  2Px = 6x^2 +64x

  P = 3x +32 . . . . . divide by 2x

6 0
3 years ago
Which graph is the sequence defined by the function f(x) = 3(2)x-17
rjkz [21]

Answer:

I am very poor on mathematics .I am sorry

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3 years ago
Jenna saves $2,500 per year in an account that earns 10% interest per year, compounded annually. Jenna will have saved in 30 yea
Vsevolod [243]

~~~~~~~~~~~~\textit{Future Value of an ordinary annuity}\\ ~~~~~~~~~~~~(\textit{payments at the end of the period}) \\\\ A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\begin{cases} A= \begin{array}{llll} \textit{accumulated amount}\\ \end{array}\\ pymnt=\textit{periodic payments}\dotfill &2500\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.1\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &30 \end{cases}

A=2500\left[ \cfrac{\left( 1+\frac{0.1}{1} \right)^{1\cdot 30}-1}{\frac{0.1}{1}} \right]\implies A=2500\left[ \cfrac{(1.01)^{30}-1}{0.1} \right] \\\\[-0.35em] ~\dotfill\\\\ ~\hfill A\approx 411235.06~\hfill

4 0
2 years ago
Solve the system y=x-3 y=-2x+3
vivado [14]

Answer:

x = 2, y= -1 Or (2, -1)

Step-by-step explanation:

Let’s solve the system using substitution. First we can set the equations equal to each other:

x-3= -2x +3

Now solve for x

3x-3= 3

3x = 6

x=2

Now that we have x, we can plug it back into one of the original equations to get y

y= x-3

y= 2-3

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Finally, the solution to the system of equations is (2, -1).

6 0
3 years ago
Read 2 more answers
Candy and Tim share a paper route. It takes Candy 85 min to deliver all the papers, and it takes Tim 65 min. How long does it ta
RSB [31]

Answer:

The time required to finish the work by both candy and Tim working together = 36.83 minute

Step-by-step explanation:

Time taken by the candy to finish the work T_{1}= 85 min

Time taken by the Tim to finish the work T_{2}  = 65 min

Thus the time taken by both to finish the work = \frac{T_1 \times\ T_2}{T_1 + T_2}

Put the values of T_{1} and T_{2}  we get ,

                    T_{} = \frac{85 \times\ 65}{85 + 65}

                    T_{} = \frac{221}{6}

                    T_{} = 36.83 minute

Thus the time required to finish the work by both candy and Tim working together = 36.83 minute

3 0
3 years ago
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