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hoa [83]
2 years ago
12

Given the figure below, find the values of x and z.

Mathematics
1 answer:
iragen [17]2 years ago
4 0

Answer:

x=6 and z=107

Step-by-step explanation:

From the figure or diagram we can say that

z+15x-17=180 ---(1)

z+11x+7=180 ---(2)

Subtracting (1) and (2)

z+15x-17-(z+11x+7)=180-180

4x-24=0

4x=24

x=6

Substitute x=6 in (2)

z+11(6)+7=180

z+66+7=180

z=180-73

z=107

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What is the following sum? Assume x20 and 20.<br> √√x²y³ +2√√x³y² + xy √√y
max2010maxim [7]

The value of the expression \sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y is 2xy\sqrt{y} + 2xy^2\sqrt{x}

<h3>How to evaluate the sum?</h3>

The attachment represents the proper format of the question

The summation expression is given as:

\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y

Expand the radicands

\sqrt{x^2y^2 * y} + 2\sqrt{x^2y^4* x} + xy\sqrt y

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xy\sqrt{y} + 2xy^2\sqrt{x} + xy\sqrt y

Add the like terms

2xy\sqrt{y} + 2xy^2\sqrt{x}

Hence, the value of the expression \sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y is 2xy\sqrt{y} + 2xy^2\sqrt{x}

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2 years ago
Problem: The mean number of bankruptcies filed per minute in the ` States in a recent year was about two. Find the probability t
tino4ka555 [31]
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Alternatively
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P(X > 5 | mean =2) = 1- p(x
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4 0
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Problem Page
leva [86]
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Answer:

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Hope this helps!

5 0
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