N; n+1; n+2 - three consecutive whole number
n + (n + 1) + (n + 2) = 195
n + n + 1 + n + 2 = 195
3n + 3 = 195 |subtract 3 from both sides
3n = 192 |divide both sides by 3
n = 64
Answer: 64; 65; 66.
It should be C but I’m not sure
Answer:
<em>The additive identity is 0. The sum of any number with the additive identity is the number itself.</em>
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I HOPE ITS RIGHT IF NOT THEN SORRY</h3>
HAVE A GREAT DAY :)