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4 years ago

Find the mean and the median of this data set: 9, 8, 5, 3, 37, 8, 4, 2. The mean is and the median is .

Mathematics

1 answer:

tatyana61 [14]4 years ago

3 0

Answer:

The mean is 9.5 and the median is 6.5.

Step-by-step explanation:

To find the mean:

Add all numbers given.

9+8+5+3+37+8+4+2= 76

Then divide by the amount of numbers (8).

76/8= 9.5

To find the median:

Re-arrange the order of the numbers from least to greatest.

2, 3, 4, 5, 8, 8, 9, 37

Count towards the middle. If there is no exact middle (like this equation), then take the two middle numbers and add them.

5+8= 13

After, divide by two since there are two numbers being added.

13/2= 6.5

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3 years ago

The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili

Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

$\lambda= 4.5$

Formula:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

a) No accidents occur in one week.

$P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111$

b) 5 or more accidents occur in a week.

$P( x \geq 5) = 1-\displaystyle \sum P(x$

c) One accident occurs today.

The mean number of accidents per day is given by

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3 years ago

5+ 3 cos ½x = 7 how to find the x?

Anon25 [30]

Answer:

$x=\pm 2 arcos(\frac{2}{3})+4k\pi$

where $k$ is an integer

Step-by-step explanation:

$5+3\cos(\frac{1}{2}x)=7$

We are going to isolate the trig expression first.

Subtract 5 on both sides:

$3\cos(\frac{1}{2}x)=2$

Divide both sides by 3:

$\cos(\frac{1}{2}x)=\frac{2}{3}$

Now since $\cos(u)$ is even then $\cos(u)=\cos(-u)$ .

So we have:

$\cos(\frac{1}{2}x)=\frac{2}{3}$

implies:

$\frac{1}{2}x=arccos(\frac{2}{3})+2k\pi$

Multiply both sides by 2:

$x=2arccos(\frac{2}{3})+4k\pi$

$-\frac{1}{2}x=arcos(\frac{2}{3})+2k\pi$

Multiply both sides by -2:

$x=-2arccos(\frac{2}{3})-4k\pi$

So we can say the solution is:

$x=\pm 2arcos(\frac{2}{3})+4k\pi$

( $k$ is an integer)

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