<span>(b+3)/7=(b-3)/6
6(b+3) = 7 (b-3)....> cross multiply
6b + 18 = 7b -21 ...>distributive property
6b - 7b = -21 -18 ...>subtract 7b to both sides then simplify
-b = -39 ...> multiply -1 to both sides
b = 39</span>
The statement is FALSE.
A constant term is also a polynomial with just one term and degree 0. The degree of the polynomial can be any non-zero integer i.e. can be 0 or greater than zero.
So the correct statement will be:
An expression must have a monomial of degree 0 or higher to be a polynomial
This is SAS. Notice you have 2 sides that are equal to each other and the vertical angle between them. Since the angle is between the 2 sides then the postulate that works is SAS.
From the above expression we get,
=》x + y = 7 - [1]
=》3x - 2y = 11 - [2]
now, let's solve :
multiplying [1] by 3
=》3x + 3y = 21
=》 3x - 2y = 11
subtracting
now, subtracting [2] from [1]
=》3x + 3y - 3x + 2y = 21 - 11
=》5y = 10
=》y = 2
now, plugging the value of y as 2 in equation [1]
=》x + y = 7
=》x + 2 = 7
=》x = 5
So, value of :