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nadezda [96]
3 years ago
12

ss="latex-formula">
Mathematics
2 answers:
Helga [31]3 years ago
5 0

Answer:

<h2>x = -49</h2>

Step-by-step explanation:

x - 6 = -55      <em>add 6 to both sides</em>

x - 6 + 6 = -55 + 6

x = -49

vlabodo [156]3 years ago
5 0
That’s too easy, x= -49
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There are 31 coins of dimes and quarters. If the number of dimes is 5 more than the number of quarters, how many quarters are th
emmasim [6.3K]

Answer:

<u>13 Quarters and 18 Dimes</u>

Step-by-step explanation:

Let D and Q stand for the numbers of Dimes(D) and Quarters(Q).  Give x and y a break, and make it easier to remember which is which.

D + Q = 31

D = Q + 5

Therefore:

D + Q = 31

(Q+5) + Q = 31

2Q + 5 = 31

2Q = 26

<u>Q = 13</u>

<u>Then D = (13+5) or 18</u>

================

Check:

D + Q = 31 ?

18 + 13 = 31  <u>YES</u>

----------------------

D = Q + 5 ?

18 = 13 + 5   <u>YES</u>

5 0
2 years ago
What is the horizontal asymptote of the function g(x)= 3(0.8)^x +6
madreJ [45]
Y = tan (x)
Y = 3x0.8x + 6
(0,0) (0,9)
3 0
2 years ago
How much grain can this container hold?
ludmilkaskok [199]

Answer:

953.78 in^3 of grain.

Step-by-step explanation:

The volume of a cylinder = π r^2 h.

For this cylinder r =  radius of the base = 9/2

= 4.5 in  and the height h = 15 in

So the volume is 3.14 * 4.5^2 * 15

= 953.78 in^3.

8 0
3 years ago
Read 2 more answers
PLZ HELP!!!!!....................
forsale [732]
It’s c. Where the two planes intersect
5 0
3 years ago
A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in
Oksi-84 [34.3K]

Answer: The concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

                               Compound X             Compound Y

272                               16400                            3870

327                                3990                             6420

So, our equations becomes

16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191

By solving these two equations, we get that

C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}

Hence, the concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

5 0
3 years ago
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