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3 years ago

12

Please please help no scams please

1 answer:

hodyreva [135]3 years ago

6 0

Answer:

between 6 and 7

Step-by-step explanation:

√39 = 6.244... which is between 6 and 7

also, you do not need a calculator if you know that the sq. rt. of 36 is 6 and the sq. rt. of 49 is 7. 39 is between 36 and 49.

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14+4*16-16/23 how the answer became 70 please explain me in steps

pickupchik [31]

Answer:

14 + 64 - 16/23

14 + 64 - 0.69 = 77.31

unless u mean 16/2

14 + 64 - 8 = 70

Step-by-step explanation:

The order of operations is a rule that tells the correct sequence of steps for evaluating a math expression. We can remember the order using PEMDAS: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

4 0

3 years ago

hichkok12 [17]

Answer: negative, positive

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Plz help will name brainiest and 100 points

xxTIMURxx [149]

Answer:

51

Step-by-step explanation:

Multiply 3 2/5 by 15

Change the mixed number to an improper fraction

3 2/5 = (5 * 3 + 2) /5 = 17/5

17/5 * 15

17 * 15/5

17 * 3

51

4 0

3 years ago

Read 2 more answers

I need help someone pls help me figure this out

s344n2d4d5 [400]

8 costumes. Not 8/0.75.

Write down 8 costumes, that's your answer.

6 0

4 years ago

The table shows a proportional relationship between the number of pounds of bananas purchased and the total cost of bananas.

Liula [17]

Answer:

Choice A, C and E

Step-by-step explanation:

<em>Your table is poorly presented</em>

Given

x y

$\begin{array}{cc} {3} & {1.47} \ \\ {5} & {2.45} \ \\ {9} & {4.41} \ \ \end{array}$

First, we calculate the constant of proportionality (k)

$k = \frac{y}{x}$

For (3,1.47)

$k = \frac{1.47}{3}$

$k = 0.49$

For (5,2.45)

$k = \frac{2.45}{5}$

$k = 0.49$

For (9,4.41)

$k = \frac{4.41}{9}$

$k = 0.49$

From the above calculations, the constant of proportionality is 0.49.

So, the usable rows must also have 0.49 as their constant of proportionality

<u>Choice A</u>

$(x,y) = (2,0.98)$

$k = \frac{0.98}{2}$

$k = 0.49$ --- <em>This is usable</em>

<em />

<u>Choice B</u>

$(x,y) = (7,4.45)$

$k = \frac{4.45}{7}$

$k = 0.64$ --- <em>This is not usable</em>

<em />

<u>Choice C</u>

$(x,y) = (6,2.94)$

$k = \frac{2.94}{6}$

$k = 0.49$ --- <em>This is usable</em>

<em />

<u>Choice D</u>

$(x,y) = (1,0.54)$

$k = \frac{0.54}{1}$

$k = 0.54$ ---- <em>This is not usable</em>

<em />

<u>Choice E</u>

$(x,y) = (8,3.92)$

$k = \frac{3.92}{8}$

$k = 0.49$ --- <em>This is usable</em>

5 0

3 years ago