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Jobisdone [24]
2 years ago
13

Find sin θ if θ is in Quadrant III and tan θ = -1/5

Mathematics
1 answer:
Alborosie2 years ago
4 0

Answer:= - sin( square root 8 over 3)sin(1/4)

Step-by-step explanation:

So I did (square root 8/3)(square root 15/4)+sin(1/4)cos(-1/3) divide that by (-1/3)(square root 15 over 4) - sin( square root 8 over 3)sin(1/4)

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0,45=\frac{45}{100} =\frac{9}{20}

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5 0
3 years ago
Two sets of quadratic expressions are shown below in various forms: Line 1: x2 + 3x + 2 (x + 1)(x + 2) (x + 1.5)2 − 0.25 Line 2:
Rainbow [258]
Line 1:
Expanding the vertex form, we have
  x² + 2·1.5x + 1.5² - 0.25 = x² +3x +2
Expanding the factored form, we have
  x² +(1+2)x +1·2 = x² +3x +2
Comparing these to x² +3x +2, we find ...
  • the three expressions are equivalent on Line 1

Line 2:
Expanding the vertex form, we have
  x² +2·2.5x +2.5² +6.25 = x² +5x +12.5
Expanding the factored form, we have
  x² +(2+3)x +2·3 = x² +5x +6
Comparing these to x² +5x +6, we find ...
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The appropriate choice is
  Line 1 only
5 0
3 years ago
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PLEASE HELP SHOW YOUR WORKING OUT Branliest
Ad libitum [116K]

Answer:

The equation of this line is therefore    y = 2x + 3.

Step-by-step explanation:

this line passes thru the points (0, 3) and (3, 9).  As we move from  (0, 3) to (3, 9), x increases by 3 and y increases by 6.  Thus, the slope of this line is

m = rise / run = 6/3, or m = 2.  Inserting the known info (m = 2, x = 0, y = 3) into y = mx + b, we get:  3 = 2(0) + b, so we see that b = 3.

The equation of this line is therefore    y = 2x + 3.

5 0
3 years ago
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