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3 years ago

14

What happens to the value of the expression 70 - 3g as g increases

1 answer:

exis [7]3 years ago

6 0

Answer:

It decreases

Step-by-step explanation:

Given the expression: 70-3g

When g=1, 70-3g=70-3(1)=70-3=67
When g=2, 70-3g=70-3(2)=70-6=64
When g=3, 70-3g=70-3(3)=70-9=61
When g=4, 70-3g=70-3(4)=70-12=58
When g=5, 70-3g=70-3(5)=70-3=55

From the above, notice that as g increases, the value of the expression decreases.

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A rental car agency charges a flat fee of $32.00 plus $3.00 per day to rent a certain car. Another agency charges a fee of $30.5

diamong [38]

Answer:

a rental car agency charges a flat rate fee of $32.00 plus $3.00 per day to rent a certain car

c = 32 + 3d

another agency charges a fee of $30.50 plus $3.25 per day to rent the same car

c = 30.50 + 3.25d

the number of days for which the cost are the same means

32 + 3d = 30.50 + 3.25d

by solving we find d = 6 days

5 0

3 years ago

How many millimeters are there in 16 meters

Anika [276]

One of the very nice features of the metric system of measurements is that there is a set of standardized prefixes that can be applied to any of the units. Some of the more common ones are
.. micro- . . . one millionth
.. milli- . . . . one thousandth
.. centi- . . . .one hundredth
.. kilo- . . . . .one thousand

Thus, one millimeter is 1/1000 = 0.001 meter. There are 1000 of them in 1 meter, so
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4 0

3 years ago

QUICK!! 18x^2+21x-60=0 pls give me the steps as well

Anton [14]

Answer:

<h2> $x1 = - \frac{5}{2}$ </h2>

$x2 = \frac{4}{3}$

Step-by-step explanation:

$18 {x}^{2} + 21x - 60 = 0$

Divide both sides of the equation by 3

$6 {x}^{2} + 7x - 20 = 0$

Write 7x as a difference

$6 {x}^{2} + 15x - 8x - 20 = 0$

Factor out 3x from the expression

$3x(2x + 5) - 8x - 20 = 0$

Factor out -4 from the expression

$3x(2x + 5) - 4(2x + 5) = 0$

Factor out 2x + 5 from the expression

$(2x + 5)(3x - 4) = 0$

When the product of factors equals 0 , at least one factor is 0

$2x + 5 = 0$

$3x - 4 = 0$

Solve the equation for X

$2x + 5 = 0$

Move constant to R.H.S and change its sign

$2x = 0 - 5$

Calculate the difference

$2x = - 5$

Divide both sides of the equation by 2

$\frac{2x}{2} = \frac{ - 5}{2}$

Calculate

$x 1= - \frac{5}{2}$

Again,

$3x - 4 = 0$

Move constant to RHS and change its sign

$3x = 0 + 4$

Calculate the sum

$3x = 4$

divide both sides of the equation by 3

$\frac{3x}{3} = \frac{4}{3}$

Calculate

$x 2= \frac{4}{3}$

Hope this helps..

Best regards!!

5 0

3 years ago

Read 2 more answers

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Marina86 [1]

Answer:

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Step-by-step explanation:

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Step 1: Define endpoint coordinates

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Step 2: Substitute and Evaluate

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$d=\sqrt{(-8)^2+(-6)^2}$

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$d=10$

8 0

3 years ago

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nadya68 [22]

Answer:

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Step-by-step explanation:

8 0

3 years ago

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