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krok68 [10]
3 years ago
6

30 ounce box of cerebral contains 12 servings

Mathematics
2 answers:
gulaghasi [49]3 years ago
8 0

Answer:

okay?

Step-by-step explanation:

is that supposed to be like is that true or false or am I just not understanding if that's a question or not

MissTica3 years ago
6 0
Where is the rest of the question
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How much did Mario spend on golfing? a. $35.20 b. $45.20 c. $47.88 d. $143.96
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$47.88 your answer and I am the most important person in the world.
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What is the lcm for 3/4and 1/2​
ioda

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1 1/2

Hope that helps!

Step-by-step explanation:

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3 years ago
What is an angle complimentary of 3?
Sergio039 [100]

Answer:

∠2

Step-by-step explanation:

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3 0
3 years ago
How cos π/3=1/2?<br>having some problems learning continuity.
Bingel [31]

You can show that \cos\frac\pi3=\frac12 by constructing a triangle.

Take two points, O(0, 0) and A(1, 0), and let B be the point on the unit circle such that the angle between the line segments OA and OB is \frac\pi3 radians.

Since both A and B lie on the circle, the line segments OA and OB both have length 1 (same as the circle's radius). We finish constructing the triangle by connect A and B.

Since OB and OA have the same length, triangle OAB is isosceles, but more than that, it's also equilateral. Why? Because the interior angles of any triangle always add to \pi radians. We know one of the angles is \frac\pi3 radians, which leaves a contribution of \frac{2\pi}3 radians between the remaining angles A and B. Angles A and B must be congruent (because OAB is isosceles), which means they also have measure \frac\pi3 radians.

Next, draw an altitude of the triangle through point B, and label the point where it meets the "base" OA, C. Since OAB is equilateral, the altitude BC is also a perpendicular bisector. That means OC has length \frac12, and by definition of \cos we have

\cos\dfrac\pi3=\dfrac{OC}{OB}=\dfrac{\frac12}1=\dfrac12

3 0
3 years ago
HELP I NEED HELP ASAP
masha68 [24]

Answer:

i think it's c but I'm rly not sure on this one...

3 0
3 years ago
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