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enyata [817]
3 years ago
9

Question 7 (5 points)

Mathematics
1 answer:
Arada [10]3 years ago
6 0

Answer: 6

That chart is confusing ash, but median just refers to the middle value. Just put them in order (4,4,6,9,12) and then find the middle. In this case it's easy as there are an odd number of values. But if you have another question where there are an odd number, for example (4,4,6,10,12,15) find the two middle numbers, 4 and 9, add them (6+10=16) and then divide by 2 to find the number in between those two. (16/2=8)

Hope this helps!

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5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

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3 years ago
A problem states: "There are 9 more pencils than pens in a container. There are 25 writing utensils in the container in all. How
Alecsey [184]
2p + 9 = 25 is the correct equation
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Can someone help me ?
GuDViN [60]

Answer:

-5,-3,-1,1,3

Step-by-step explanation:

range= y

really need brainliest!!

4 0
3 years ago
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A certain roller coaster can accommodate 1,600 riders per hour. A digital sign states there are 345 people in line. If you get i
oksano4ka [1.4K]
By multiplying 1,600×345
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4 years ago
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Javier has four cylindrical models. The heights, radii, and diagonals of the vertical cross-sections of the models are shown in
Ronch [10]

The model in which the lateral surface meets the base at right angle is : Model 1.

<h3>What is a lateral surface?</h3>

The lateral surface of an object is all surfaces  of that object excluding its base and top.

Analysis:

To know the exact model, we check for the models in which their dimensions form a Pythagorean triplet otherwise a right-angled triangle.

For Pythagorean triplet, the square of the diagonal must be equal to the sum of squares of the other two sides.

Model 1

Diagonal = 50cm, radius = 14cm, lateral height = 48cm

(50)^{2} = (14)^{2} + (48)^{2}

2500 = 196 + 2304

2500 = 2500. Forms Pythagorean triplet

Model 2

Diagonal= 37cm, radius = 6cm  lateral height = 35cm

(37)^{2} = (35)^{2}+ (6)^{2}

1369 = 1225 +36

1369 \neq 1261

Model 3

Diagonal = 60cm, radius = 20cm  lateral height = 40cm

(60)^{2} = (20)^{2} + (40)^{2}

3600 = 400 + 1600

3600 \neq 2000

Model 4

Diagonal = 30cm, radius = 24cm, lateral height = 9cm

(30)^{2} = (24)^{2} + (9)^{2}

900 = 576 + 81

900 \neq 657

Therefore the lateral surface model 1 meets the base at right angle

In conclusion,  the lateral surface of model 1 meets the base at right angles as the dimensions form a right-angled triangle.

Learn more about Pythagorean triplet: brainly.com/question/20894813

#SPJ1

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2 years ago
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