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3 years ago

How do you find the slope if a line of two points are given?

Mathematics

2 answers:

TiliK225 [7]3 years ago

7 0

If it is the two ordered pairs that are given then use the following slope formula.

$m = \frac{y_2-y_1}{x_2-x_1}$

also known as m = rise / run

Ket [755]3 years ago

5 0

Step-by-step explanation:

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About how many people do you think will get the virus

dmitriy555 [2]

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8 0

2 years ago

Read 2 more answers

Can you please help me solve for the area

ycow [4]

Answer:

area is equal to 198 cm^2

Step-by-step explanation:

the height h of the left triangle can be obtained by

Pytagoras theorem:

$5^2+h^2=13^2\\25+h^2=169\\h^2=169-25\\h^2=144\\h=\sqrt{144} \\h=12$

the, the area of the left triangle is

$A_1=\frac{5*12}{2} \\A_1=5*6\\A_1=30$

the area of the right triangle is

$A_2=\frac{2*12}{2} \\A_2=12$

and the area of the rectangle in the middle is

$A_3=(13)(12)\\A_3=156$

Por tanto, el area total sera

$A=A_1+A_2+A_3\\A=30+12+156\\A=198$

8 0

2 years ago

Solve the equation using square roots 6x2=54

o-na [289]

6x^2 = 54

x^2 = 9

x = -3, 3

Hope this helps!

4 0

2 years ago

A tank has capacity 6 L and initially contains 11 mg of salt dissolved in 3 L of water. A solution containing 1 mg/L of salt ent

BlackZzzverrR [31]

Answer:

The answer is below

Step-by-step explanation:

a) The maximum capacity of he tank is 6 L and initially it contains 11 mg of salt dissolved in 3 L of water. Solution enters the tank at a rate of 3 L/hr, therefore in x hours, the amount of water that have entered the tank = 3x.

Solution also leaves the tank at a rate of 2L/hr, therefore in x hours, the amount of water that have left the tank = 2x

Hence the amount of water present in the tank at x hours is given as:

3 + 3x - 2x = 3 + x

The time taken to full the tank can be gotten from:

3 + x = 6

x = 6 - 3

x = 3 hr

$\frac{dQ}{dx}=3-\frac{2Q}{3+x}\\ \\\frac{dQ}{dx}+\frac{2Q}{3+x}=3\\\\let\ u'=\frac{2u}{3+x}\\\\\frac{u'}{u}=\frac{2Q}{3+x}\\\\ln(u)=2ln(3+x)\\\\u=(3+x)^2\\\\(3+x)^2Q]'=3(3+x)^2\\\\(3+x)^2Q=(3+x)^3+c\\\\Q(0)=11\\\\(3+0)^2(11)=(3+0)^3+c\\\\x=72\\\\Q=x+3+\frac{72}{(x+3)^2}\\ \\Q(3)=3+3+\frac{72}{(3+3)^2}=8\ mg$