X^2+y^2 = 16
can be written as
(x-0)^2+(y-0)^2 = 4^2
We see that the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
where
(h,k) = (0,0) is the center
r = 4 is the radius
The polar form of the equation is simply r = 4. Why is this? Because the radius is fixed to be 4 no matter what happens with theta. As theta goes from 0 to 360, the points generated all form a circle centered at (0,0) with radius 4.
Answer: r = 4
<u><em>Answer:</em></u>
<u><em>Option A</em></u>
<u><em>Step-by-step explanation:</em></u>
<u><em>-(12 x 2) x (-6) = -12 x (2 x b)</em></u>
<u><em>=> -24 x -6 = -12 x 2b</em></u>
<u><em>=> 144 = -24b</em></u>
<u><em>=> b = -6</em></u>
<u><em>Hoped this helped.</em></u>
Step-by-step explanation:
u know u can download math go and u just take a picture and it will give u the answer
Answer:
145 yards squared
Step-by-step explanation:
So the area of the base is area of a square with side length of 5 yards 
The area of one triangular face base times height divided by two and then simply multiplied by 4 because there are 4 triangular faces.

So the total surface area is
yards squared
Answer:
The correct answer would be 
Step-by-step explanation:
given
we want to solve for a
How?
We can do this by using basic algebra ( isolating the variable (a ))
Step 1 subtract
from each side

now we have 
step 2 take the square root of each side

we're left with
Hence your answer is A