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andre [41]
3 years ago
12

Write an equivalent expression for 4.5x(2 - 6)

Mathematics
2 answers:
ki77a [65]3 years ago
5 0

4.5x(2 - 6) \\  \\ 1. \: 4.5x \times  - 4 \\ 2. \:  =  - 18x

Simora [160]3 years ago
5 0

\text{Hey there!}

\text{You could solve this equation by distributing}

\text{The Algebraic I formula for distribution is: a(b + c) = ab + ac}

\text{4.5x(2 - 6)}\\\text{4.5x(2) = 9x}\\\text{4.5x(-6)= -27x}

\text{Combine like terms: 9x - 27x = ?}

\text{Solve that}\uparrow\text{you should get the rest of -18x}

\boxed{\boxed{\text{Answer: -18x}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

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Simplify the following expression:<br><br> (66)4
iren [92.7K]

Step-by-step explanation:

Given

( {6}^{6})^{4}  \\  =  {6}^{6 \times 4}  \\  =  {6}^{24}  \\  = 4.7383813e18

3 0
3 years ago
Which graph representative this function
nalin [4]

Answer:

in graph A the vertex is (0,0)

in graph B the vertex is (0,3)

in graph C the vertex is (0,-3)

And in graph D the vertex is (0,-1)

The axis of symmetry for all of the is 0

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8 0
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I'm confused on how to create ratios
Rzqust [24]

Answer:

Latoya:

cran : lem = 2 1/5 : 1 4/5

= 11/5 : 9/5

= 11 : 9

Lem : total = 9 : 20

Parker:

cran : lem = 2 1/2 : 3 1/2

= 5/2 : 7/2

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Step-by-step explanation:

8 0
2 years ago
Help please ASAP !!!!
mixas84 [53]
Your answer is -4<span>√6. Hope this helps :)</span>
5 0
3 years ago
A survey of 46 college athletes found that 24 played volleyball, while 22 played basketball. a) If we pick one athlete survey pa
PSYCHO15rus [73]

Answer:

A) \dfrac{11}{23}

B) \dfrac{88}{345}

Step-by-step explanation:

A survey of 46 college athletes found that

  • 24 played volleyball,
  • 22 played basketball.

A) If we pick one athlete survey participant at random,  the probability they play basketball is

P_1=\dfrac{22}{46}=\dfrac{11}{23}

B) If we pick 2 athletes at random (without replacement),

  • the probability we get one volleyball player is \dfrac{24}{46}=\dfrac{12}{23};
  • the probability we get another basketball player is \dfrac{22}{45} (only 45 athletes left).

Thus, the probability we get one volleyball player and one basketball player is

P_2=\dfrac{12}{23}\cdot \dfrac{22}{45}=\dfrac{88}{345}

5 0
3 years ago
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