Answer:
4 x 4 = 16, 16 divided by 2 ( x 1/2 ) = 8
8 x 2 = 16(area of two triangles)
8 x 4 = 32(area of base below)
5.7 x 8 = 45.6 (area of slant)
4 x 8 = 32(area of the rectangle behind the figure)
Add all the given areas:
16 + 32 + 45.6 + 32 = 125.6 in^2 is your answer
Angle E, since it is a right triangle the other two have to be acute.
Answer:
I made the problem in a photo so you could do it for the next
Intersection
Hope i helped :)
Answer:
15<x<27
Step-by-step explanation:
Rule for the sides of a triangle:
The sum of the two smallest sides of a triangle must be greater than the biggest side.
In this question:
Sides of 6, 21 and x. We have to find the range for x.
If 21 is the largest side:
Two smallest are 6 and x.
x + 6 > 21
x > 21 - 6
x > 15
If x is the largest side:
Two smallest and 6 and 21. So
21 + 6 > x
27 > x
x < 27
Then
x has to be greater than 15 and smaller than 27. So the answer is:
15<x<27