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Mumz [18]
3 years ago
12

Sally is playing a board game and rolls two number cubes. Let A = {the sum of the number cubes is odd} and let B = {the sum of t

he number cubes is divisible by 2}. List the outcomes in A ∩ B.
Mathematics
2 answers:
Iteru [2.4K]3 years ago
7 0

Answer: A∩B is an empty set.

A∩B=\phi

OR

A∩B= { }


Step-by-step explanation:

Given : A = {the sum of the number cubes is odd}

and  B = {the sum of the number cubes is divisible by 2}

We know that odd numbers is not divisible by 2 .

Therefore, the both set have no element common.

Thus, their intersection will be an empty set.

A∩B is an empty set.

A∩B=\phi

OR

A∩B= { }


slega [8]3 years ago
4 0
The Answer to the question is { }.<span>

This is because there are no answers that are odd and divisible by 2.</span>
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6 0
3 years ago
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Lina20 [59]

Answer:

A

Step-by-step explanation:

To sovle this we must combine the numbers togther and the variables togther.

We have:

8c+6-3c-2

Lets take out the c's and combine them:

8c -3c

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Now lets take out the numbers:

6-2

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4

Now lets put these back together and we get the expression:

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Hope this helps! :D

8 0
3 years ago
A road has a scale of 1:50 000 The length of a road on the map is 8.5cm.Work out the length of the real road in kilometres
uranmaximum [27]

The answer is 2.1 Km. Hope this helps!

5 0
3 years ago
Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m
Molodets [167]

Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1).

The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

8 0
3 years ago
A company makes wax candles in the shape of a solid sphere. Suppose each candle has a diameter of 15 cm. If
jekas [21]

We have been given that a company makes wax candles in the shape of a solid sphere. Each candle has a diameter of 15 cm. We are asked to find the number of candles that company can make from 70,650 cubic cm of wax.

To solve our given problem, we will divide total volume of wax by volume of one candle.

Volume of each candle will be equal to volume of sphere.

V=\frac{4}{3}\pi r^3, where r represents radius of sphere.

We know that radius is half the diameter, so radius of each candle will be \frac{15}{2}=7.5 cm.

\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot (7.5\text{ cm})^3

\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot 421.875\text{ cm}^3

\text{Volume of one candle}=1766.25\text{ cm}^3

Now we will divide 70,650 cubic cm of wax by volume of one candle.

\text{Number of candles}=\frac{70,650\text{ cm}^3}{1766.25\text{ cm}^3}

\text{Number of candles}=\frac{70,650}{1766.25}

\text{Number of candles}=40

Therefore, 40 candles can be made from 70,650 cubic cm of wax.

8 0
3 years ago
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