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e-lub [12.9K]
3 years ago
15

Write this in y=ax^2+b form: y=(x-5)^2 - 2

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
5 0
y=(x-5)^2-2\\
y=x^2-10x+25-2\\
y=x^2-10x+23

MrMuchimi3 years ago
3 0
Expand (x - 5)^2

(x - 5)^2 = (x - 5)(x - 5)

Multiply all the terms in the first parenthesis to all the terms in the 2nd:

x * x = x^2
x * -5 = -5x
-5 * x = -5x
-5 * -5 = 25

So we have:

x^2 - 5x - 5x + 25

Combine like terms:

x^2 - 10x + 25

Plug it back in:

y = (x - 5)^2 - 2

y = x^2 - 10x + 25 - 2

Combine like terms:

y = x^2 - 10x + 23
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Now we find the common numbers. One doesn’t count as when multiplied later on, it will not change anything.

60: 2, 4, 5, 10, 20

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The highest common factor is 20 because it’s, well, the highest number.

D. Do the same thing for D.

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E. Do the same thing with E.

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1,000: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

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3 0
3 years ago
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What value of x makes this equation true?
UkoKoshka [18]

Answer:

The correct answer is D

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What is the solution to this equation? 7x-12x-5=-45+15 A. x=-5 B. x=5 C. x=7 D. x=-7
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2a plus 3/4b

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Finally simplify.

8 0
3 years ago
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