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3 years ago

Find the distance between each pair of points 8) (2, 6), (5, 10) 9) (-3,-10), (-3,5)

Mathematics

1 answer:

Lapatulllka [165]3 years ago

4 0

Answer:

8) answer=5 9)answer=15

Step-by-step explanation:

all you have to do is replace in the following formula

$\sqrt{(x2-x1)^{2}+ (y2-y1)^{2}} =d$

Where

X1: is the first number of the first point

Y1: is the second number of the first point

X2: is the first number of the second point

Y2: is the second number of the second point

you replace in the formula and solve

I attach solution

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Allison read 4/8 of an hour everyday of the week. How many hours does she read each week

Tema [17]

Answer:

3 1/2 hours

Step-by-step explanation:

Multiply 4/8 by 7 and you get 28/8 whihc reduces to 3 4/8 and 4/8 can be simplified to 1/2

6 0

2 years ago

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Gave needs 60 liters of 40% acid solution he currently has 20% solution and 50% solution how many liters of each does he need to

Rudiy27

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentration\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{20\% sol'n}&x&0.20&0.20x\\
\textit{50\% sol'n}&y&0.50&0.50y\\
-----&-----&-------&-------\\
mixture&60&0.40&(60)(0.40)
\end{array}$

notice above... we use the decimal format for the percentage, thus 20% is really just 20/100, 40% is 40/100 and so on.

so.. whatever "x" and "y" amounts are, we know they have to add up to 60 Liters, that is x+y = 60

and whatever the concentration amount of each is, it must add up to (60)(0.40), that is 0.20x+0.50y=(60)(0.40)

thus $\bf \begin{cases}
x+y=60\implies \boxed{y}=60-x\\\\
0.20x+0.50y=(60)(0.40)\\
----------\\
0.20x+0.50\left( \boxed{60-x} \right)=(60)(0.40)
\end{cases}$

solve for "x", to see how much of the 20% solution will be needed

what about "y"? well, y = 60 - x

7 0

3 years ago

What kind of shift does the graph have? y = -sin (x-1) from y = sin(x)

Mademuasel [1]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}
\end{array}
\\\\
-------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)$

now, with that template in mind, let's see

$\bf \begin{array}{lllll}
y=&-1sin(&1x&-1)&+0\\
&A&B&C&D
\end{array}
\\\\\\
\textit{horizontal shift of }\cfrac{C}{B}\implies \cfrac{-1}{1}\implies -1
\\\\\\
\textit{A is negative, so is flipped upside-down}$

8 0

3 years ago

The lines below are parallel. If the slope of the green line is –3, what is the slope of the red line?

Fed [463]

The slope of the red line should be -3 as well since they are parallel lines

6 0

3 years ago

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Find the hypotenuse of a triangle with a base of 11cm and height of 9cm

netineya [11]

<span>Use Pythagorean Theorem :
</span><span>Hypotenuse
</span>c²=a²+b²
c²= √9²+11²
c=√202
c=14.21

7 0

3 years ago