So in order for us to know the area of the square that is not covered by the circle, we need to find first both the areas of the square and the circle.
So for the area of the square it is A = sxs. And for the circle is A = pi*r^2.
Let us find the area of the square first given that the side is 3 inches.
So A = 3*3
A = 9 square inches.
Next is the area of the circle. Since the center of the circle is the same with the center of the square, the radius would be 1.5.
SO, A = (3.14)(1.5)^2
A = 2.25 (3.14)
A = 7.065 square inches.
Next, we deduct the area of circle from area of square and the result would be 1.935 <span>in². So the answer for this would be option B.
Hope this answer helps.</span>
So it would be x12 to the 2nd power, kinda hard to explain but i really hope this helped
Answer:
option b)
tan²θ + 1 = sec²θ
Step-by-step explanation:
The Pythagorean trigonometric identity is a trigonometric identity expressing the Pythagorean theorem in terms of trigonometric functions.
hypotenuse² = height² + base²
Given in the questions are some pythagorus identities which except of b) are all incorrect as explained below.
<h3>1)</h3>
sin²θ + 1 = cos²θ incorrect
<h3>sin²θ + cos²θ = 1 correct</h3><h3 /><h3>2)</h3>
by dividing first identity by cos²θ
sin²θ/cos²θ + cos²θ/cos²θ = 1/cos²θ
<h3>tan²θ + 1 = sec²θ correct</h3><h3 /><h3>3)</h3>
1 - cot²θ = cosec²θ incorrect
by dividing first identity by sin²θ
sin²θ/sin²θ + cos²θ/sin²θ = 1/sin²θ
<h3>1 + cot²θ = cosec²θ correct</h3><h3 /><h3>4)</h3>
1 - cos²θ = tan²θ
not such pythagorus identity exists
Answer:
My answer would be B.
Step-by-step explanation:
Triangle angles have to add up to a total of 180 degrees. B. has a very close measures in angles. I am sorry if this is not the answer. But let me know.
