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4 years ago

Find (f°g)(x) f(x)=x^2-1, g(x)=3x-2

Mathematics

1 answer:

Bess [88]4 years ago

5 0

F°g(x) = (3x-2)² -1
= 3x(3x-2)-2(3x-2) -1
= 9x² -6x-6x+2-1
=9x²-12x+1

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Step-by-step explanation:

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3 years ago

Write the explicit rule <br> a1=5 d=4

geniusboy [140]

Let a_1 = 5

Let d = 5 = common difference

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3 years ago

Can you plz help me solve this<br>simplify the expression <br>8w-13w+6-20-10w

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3 years ago

Jayden has $0.56 worth of pennies and nickels. He has a total of 20 pennies and nickels altogether. Determine the number of penn

Aneli [31]

Answer:

11 pennies and 9 nickels

Step-by-step explanation:

Set up a system of equations where p is the number of pennies and n is the number of nickels:

p + n = 20

0.01p + 0.05n = 0.56

Solve by substitution by rearranging the first equation:

p + n = 20

p = 20 - n

Then, plug this in as p into the second equation, and solve for n:

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3 years ago

What is [[3^3-7)·5)/10]+((1+3+6+9)-)]

yanalaym [24]

Answer:

$\left(\left(3^3-7\right)\frac{5}{10}\right)+\left(\left(1+3+6+9\right)-1\right)=28$

Step-by-step explanation:

As far as I am able to observe from the statement of your question, the expression is:

$\left[[\left(3^3-7\right)\cdot \frac{5}{10}\right]+\left(\left(1+3+6+9\right)-1\right)$

So, lets solve this expression, which anyways would clear your concept

Considering the expression

$\left[[\left(3^3-7\right)\cdot \frac{5}{10}\right]+\left(\left(1+3+6+9\right)-1\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=\left(3^3-7\right)\frac{5}{10}+1+3+6+9-1$

Lets first solve $\left(3^3-7\right)\frac{5}{10}$

As $3^3=27$

$=\frac{5}{10}\left(27-7\right)$

$=\frac{1}{2}\left(27-7\right)$

$=20\cdot \frac{1}{2}$

$=10$

So,

$\left(3^3-7\right)\frac{5}{10}+1+3+6+9-1 = 10+1+3+6+9-1$

= $28$

Therefore,

$\left(\left(3^3-7\right)\frac{5}{10}\right)+\left(\left(1+3+6+9\right)-1\right)=28$

Keywords: Expression solving

Learn more about solving expression from brainly.com/question/4687406

#learnwithBrainly

7 0

3 years ago