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dangina [55]
3 years ago
9

A limited edition poster increases in value each year with an initial value of $18. After one year and an increase of 15% per ye

ar, the poster is worth $20.70. Which equation can be used to fund the value, y, after x years?
Mathematics
1 answer:
USPshnik [31]3 years ago
7 0

We have been given that a limited edition poster increases in value each year with an initial value of $18. After one year and an increase of 15% per year, the poster is worth $20.70.  

We will use exponential growth formula to find our required equation.

We know that an exponential function is in form y=a\cdot (1+r)^x, where

a = Initial value,

r = Growth rate in decimal form,    

x = Time.    

Let us convert 15% into percentage.

15\%=\frac{15}{100}=0.15

Initial value is 18.

Upon substituting these values in above formula, we will get:

y=18(1+0.15)^x

y=18(1.15)^x

Let us check our function by finding the value of poster after one year as:

y=18(1.15)^1

y=18(1.15)

y=20.70

Since the value of poster after 1 year matched with our findings, therefore, the equation y=18(1.15)^xcan be used to fund the value, y, after x years.

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<h3>maximum height the ball reaches</h3>

The maximum height the ball reaches is calculated as follows;

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at maximum height, final velocity = 0

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Thus, the maximum height the ball reaches is 65.92 m.

The time taken for the ball to reach the maximum height is 3.06 seconds.

The time taken for the ball to hit the ground is 6.12 seconds.

Learn more about maximum height here: brainly.com/question/12446886

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let

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sleeping bags = 2

campstools = 3

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sleeping bags = s

campstools = c

If

t = 5c

s = c + 6

Total = t + 2s + 3c

212 = 5c + 2(c + 6) + 3c

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