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4 years ago

Identify the decimals labeled with the letters A,B and C on the scale below

Mathematics

1 answer:

romanna [79]4 years ago

7 0

C= 28.8
A=29.9
B=30.1

Just count the lines.

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3 years ago

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sashaice [31]

Answer:

1. -32

2. -46

Step-by-step explanation:

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2. When you have a negative number and when you have a postive number and you are subtracting your answer has to be a negative answer

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4 years ago

Pls help Describe how to find the product of the two terms 3x^2y^5 and 4x^3y^7

zvonat [6]

Answer:

12 x^5y^12

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3x^2y^5 * 4x^3y^7

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3*4 = 12

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3 years ago

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A distribution of scores for a test of life stressors has a mean of µ = 125 and standard deviation of σ = 15. The researcher cal

laila [671]

Answer:

The mean and standard deviation for the z-scores in this distribution are 0 and 1 respectively.

Step-by-step explanation:

Let the random variable X follow a Normal distribution with mean μ and standard deviation σ.

The z-scores are standardized form of the raw scores X. It is computed by subtracting the mean (μ) from the raw score x and dividing the result by the standard deviation (σ).

$z=\frac{x-\mu}{\sigma}$

These z-scores also follow a normal distribution.

The mean is:

$E(z)=E[\frac{x-\mu}{\sigma} ]=\frac{1}{\sigma}\times [E(x)-\mu] =\frac{1}{\sigma}\times [\mu-\mu]=0$

The standard deviation is:

$Var(z)=Var[\frac{x-\mu}{\sigma} ]=\frac{1}{\sigma^{2}}\times [Var(x)-Var(\mu)] =\frac{\sigma^{2}-0}{\sigma^{2}}=1\\SD(z)=\sqrt{Var(z)}=1$

Thus, the mean and standard deviation for the z-scores in this distribution are 0 and 1 respectively.

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3 years ago