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vredina [299]
3 years ago
13

A college student earned $246, $288, $234, and $276 over a four-week period. How much must he earn during the fifth week to have

average earnings of $255 for the five weeks?
Mathematics
1 answer:
hjlf3 years ago
7 0

255 \times 5 = 1275

1275 - 246 - 288 - 234 - 276 \\  = 231

Answer : He must earn $231 during the fifth week.

Hope this helps. - M
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Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y
professor190 [17]

Answer:

Required total charge is 256\pi coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

x^2=y^2\leq 16 so that the charge density at (x,y) is,

\rho (x,y)=2x+2y+2x^2+2y^2

To find total charge on the disk let Q be the total charge and x=r\cos\theta,y=r\sin\theta so that,

Q={\int\int}_Q\rho(x,y) dA                where A is the surface of disk.

=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA

=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta

=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta

=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta

=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta

=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi

=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi

=256\pi

Hence total charge is 256\pi coulombs per square meter.

3 0
3 years ago
What is the product of the binomials (4a – 1) and (2b + 3)?
galben [10]

Answer:

D. 8ab+12a-2b-3

Step-by-step explanation:

You are basically combining like terms

8 0
3 years ago
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Find the area of the segment (unshaded area) of Circle G with radius 4in. Round to the nearest tenth.
Romashka [77]

Angle is 90°

The sector is 1/4 th of circle

Area of sector

  • πr²/4
  • π(4)²/4
  • 4πin²

Triangle is right angled

Area

  • 1/2(4)²
  • 16/2
  • 8in²

Area of unshaded region

  • 4π-8
  • 4(π-2)
  • 4(3.14-2)
  • 4(1.14)
  • 4.56in²
4 0
1 year ago
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James has a balance of $1,230 on his credit card that has an APR of 24%. He currently pays the minimum monthly payment of
ArbitrLikvidat [17]

Answer:

the answer is B James can eliminate $25 from Food/Clothes and $27 from Entertainment.

hope it helps!

7 0
3 years ago
F(x) = x2 + 1 g(x) = 5 – x (f – g)(x) =
Blizzard [7]

Answer:

x^2+x-4

Step-by-step explanation:

(f-g)=(x^2+1)-(5-x)

     =x^2+1-5+x

     =x^2+x-4

4 0
3 years ago
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