Answer:
Angle 2 = 27 and Angle 1 = 135
Step-by-step explanation:
Let x = angle 2
Let 5x = angle 1
5x+x=162
6x=162
x=27
Angle 1 = 5(27)
Angle 1 = 135
Answer:
48/7
Step-by-step explanation:
= 3 <u> </u><u>1</u><u> </u> × 2 <u> </u><u>1</u><u> </u>
5. 7
= <u> </u><u>1</u><u>6</u><u> </u> × <u> </u><u>1</u><u>5</u><u> </u>
5. 7
= <u> </u><u>2</u><u>4</u><u>0</u><u> </u> , if we divide both numbers by 5 we get;
35
= <u> </u><u>4</u><u>8</u><u> </u>
7
Answer:
The answer is 5.55
Step-by-step explanation:
I assume that there is an operato ^ missing in each function and that the right functions are:
f(m) = (m+40)^2 + 10 and
g(m) = (m+12)^2 - 50
C(m) = f(m) + g(m)
To perform that sum you need to expand the two square parentheses, this way:
f(m) = (m+40)^2 + 10 = m^2 + 80m + 1600 + 10 = m^2 + 80m + 1610
g(m) = (m+12)^2 - 50 = m^2 + 24m + 144 - 50 = m^2 +24m + 94
Now you can add f(m) + g(m) = 2m^2 + 104m + 1704
Answer: c(m) = 2m^2 + 104m + 1704
91 is your composite number
Everything else is prime.