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Feliz [49]
3 years ago
7

There are (32)4 ⋅ 30 bacteria in a Petri dish. What is the total number of bacteria in the dish?

Mathematics
1 answer:
NeX [460]3 years ago
5 0
Just multiply (32) times 4 and then that total multiply by 30, 

32 x 4 = 128, 128 x 30 = 3840
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I need help what is this?
zhuklara [117]

Answer:

picture from Goldbach's conjecture.

Step-by-step explanation:

Goldbach's conjecture is one of the oldest and best-known unsolved problems in number theory and all of mathematics. It states:

Every even integer greater than 2 is the sum of two primes.

The conjecture has been shown to hold for all integers less than 4 × 10^18, but remains unproven despite considerable effort.

So on the red and blue axes you see primes. The list of black numbers are even numbers.

8 0
3 years ago
This is very hard for me I need to know how to do it
insens350 [35]

The zeros of a function are the values of x that make the function be equal to zero.

When graphing a quadratic equation, the graph is a parabola, and the zeros of the function are the x-intercepts of the graph, which are the points where the graph intersects the x-axis.

So, if the zeros of this function are x = -8 and x = 2, that means the parabola crosses the x-axis at x = -8 and x = 2.

Therefore the correct option is the first one.

6 0
8 months ago
SOS PLZ IDK THIS VERY WELL NEED HELP
zaharov [31]

Answer:

1. a. 25(1) + 10(2) + 3(3) + 10(4) = 94/140 = .671

2. b. Mark’s average < Jay’s average

Step-by-step explanation:

1. What is Mark’s slugging average?

The slugging average gives more weight to the multi-base hits (compared to single-base hits) in opposition with the batting average.

So, a single hit is worth 1 point, a double is worth 2 points, a triple 3 points and a homerun is worth 4 points.  It's a weighted average calculation.

Mark had 25 singles, 10 doubles, 3 triples and 10 homeruns during 140 presences 140 at bat.

25(1) + 10(2) + 3(3) + 10(4) = 94/140 = .671

2. How does Mark's average compares to Jay's?

Let's first calculate Jay's slugging average then we'll be able to decide.

Jay had 10 singles, 6 doubles, 5 triples and 14 homeruns in 90 presences.

10 (1) + 6 (2) + 5 (3) + 14 (4) = 10+12+15+56 = 93 / 90 = 1.033

We can definitely say that Mark's slugging average (0.671) calculated above is lower than Jay's average (1.033).  So,

b. Mark’s average < Jay’s average

8 0
3 years ago
Over the course of 5 games, a football team scores an average of 14 points with an absolute deviation of 4 points. What were the
qwelly [4]
Me don’t know svyistiytsuytsuyts
3 0
2 years ago
a laboratory, you determine that the density of a certain solid is 5.23×10−6kg/mm3. Convert this density into kilograms per cubi
Vedmedyk [2.9K]

Answer:

5.23\times 10^{-6}\ kg/mm^3=5230\ kg/m^3          

Step-by-step explanation:

Given : The density of a certain solid is 5.23\times 10^{-6} kg/mm³.

To find : Convert this density into kilograms per cubic meter ?

Solution :

We know that,

1\ m^3=10^9\ mm^3

or 10^9\ mm^3=1\ m^3

So, 1 mm^3=\frac{1}{10^9}\ m^3

1 mm^3=10^{-9}\ m^3

Converting 5.23\times 10^{-6} kg/mm³ into kg/m³,

5.23\times 10^{-6}\ kg/mm^3=\frac{5.23\times 10^{-6}}{10^{-9}}\ kg/m^3

5.23\times 10^{-6}\ kg/mm^3=5.23\times 10^{-6+9}\ kg/m^3

5.23\times 10^{-6}\ kg/mm^3=5.23\times 10^{3}\ kg/m^3

5.23\times 10^{-6}\ kg/mm^3=5230\ kg/m^3

Therefore, 5.23\times 10^{-6}\ kg/mm^3=5230\ kg/m^3

6 0
3 years ago
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