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BabaBlast [244]
2 years ago
15

I will give you brainlyest and give you points​

Mathematics
1 answer:
allsm [11]2 years ago
5 0

Answer:

VOL_cone is 70.7

which is LESS THAN

the vol of cylinder. VOL_cyl is 71.6

Step-by-step explanation:

Volume of a cone:

V= (1/3)pi•r^2 • h

=(1/3)pi•3^2 • 7.5

= 70.7 cubic inches

(rounded to tenths this is the same if you use a pi key on the calculator or if you use 3.14)

The Volume of a cylinder:

V = pi•r^2 • h

= pi• 2.25^2 • 4.5

= 71.6 cubic inches

(more accurate with pi key, using 3.14 it rounds to 71.5)

The last blank could be the words "less than" but if they are asking for a fraction or percent, calculate by putting the big number on the bottom and the smaller number on top.

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Lacey's mom makes her a birthday cake in the shape of an "L" . Lacey loves frosting, so her mom covers the entire outside of the
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Answer:

Step-by-step explanation:

I’m not sure u didn’t even add numbers

8 0
2 years ago
Help please asap. Also please teach how to do this type of problem
lana [24]

Answer:

64m^{2}

Step-by-step explanation:

  • TSA (total surface area) of cuboid= 2(lw+wh+hl)

and the problem said one small cube with 1m width that means it also has 1m length and height

so lets count the cubes for the height, length and width

  1. Height contains 4 cubes (4m)
  2. Length contains 4 cubes also (4m)
  3. Width contains 2 cubes (2m)

Now lets put the givens we got from the figure in the formula of TSA

2*(4*2+4*2+4*4)=64

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3 years ago
For the equation y=5x+4, determine the value of y when x=−1.
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Step-by-step explanation:

y = 5x + 4, x = -1

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5 0
3 years ago
Find the zeros of the following polynomial functions, with their multiplicities. (a) f(x)= (x +1)(x − 1)(x² +1) (b) g(x) = (x −
larisa [96]

Answer:

a) zeros of the function are x = 1 and, x = -1

b) zeros of the function are x = 2 and, x = 4

c) zeros of the function are x = \frac{3}{2}

d) zeros of the function are x = \frac{-4}{3}  and, x = 17

Step-by-step explanation:

Zeros of the function are the values of the variable that will lead to the result of the equation being zero.

Thus,

a) f(x)= (x +1)(x − 1)(x² +1)

now,

for the (x +1)(x − 1)(x² +1) = 0

the condition that must be followed is

(x +1) = 0 ..........(1)

or

(x − 1) = 0 ..........(2)

or

(x² +1) = 0 ...........(3)

considering the equation 1, we have

(x +1) = 0

or

x = -1

for

(x − 1) = 0

x = 1

and,

for (x² +1) = 0

or

x² = -1

or

x = √(-1)         (neglected as it is a imaginary root)

Thus,

zeros of the function are x = 1 and, x = -1

b) g(x) = (x − 4)³(x − 2)⁸

now,

for the (x − 4)³(x − 2)⁸ = 0

the condition that must be followed is

(x − 4)³ = 0 ..........(1)

or

(x − 2)⁸ = 0 ..........(2)

considering the equation 1, we have

(x − 4)³ = 0

or

x -4 = 0

or

x = 4

and,

for (x − 2)⁸ = 0

or

x - 2 = 0

or

x = 2        

Thus,

zeros of the function are x = 2 and, x = 4

c) h(x) = (2x − 3)⁵

now,

for the (2x − 3)⁵ = 0

the condition that must be followed is

(2x − 3)⁵ = 0

or

2x - 3 = 0

or

2x = 3

or

x = \frac{3}{2}

Thus,

zeros of the function are x = \frac{3}{2}

d)   k(x) =(3x +4)¹⁰⁰(x − 17)⁴

now,

for the (3x +4)¹⁰⁰(x − 17)⁴ = 0

the condition that must be followed is

(3x +4)¹⁰⁰ = 0 ..........(1)

or

(x − 17)⁴ = 0 ..........(2)

considering the equation 1, we have

(3x +4)¹⁰⁰ = 0

or

(3x +4) = 0

or

3x = -4

or

x = \frac{-4}{3}

and,

for (x − 17)⁴ = 0

or

x - 17 = 0

or

x = 17        

Thus,

zeros of the function are x = \frac{-4}{3}  and, x = 17

7 0
3 years ago
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