Hey Brion,
1) <span>Evaluate 2A - 3B for A = 7 and B = -2.
To solve this start by filling in the variables.
2(7) - 3(-2)
Now multiply, remember that a positive times a negative is a negative.
14 - (-6)
Finally, subtract. Remember, Keep, Change, Change (KCC). Keep the first number, change symbol (for subtraction use addition), and change the negative number to a positive number.
14 + 6 = 20
</span><span>2) If x = -3, then x 2-7x + 10 equals
Start by filling in the variables.
-3(2) - 7(-3) + 10
Now follow PEMDAS (Parentheses, Exponents, Multiplication & Division, Addition & Subtraction) to solve. Remember K.C.C (no. 1 above)
</span>-3(2) - 7(-3) + 10
<span>(-6) - (-21) + 10
(-6) + (21) + 10
15 + 10
25*****See NOTE!***
</span><span>_____________________________________________________________
Note: For #2 you may be missing a symbol between the first "x" and "2" because the answer I got above (25) is not one of your choices. Let me know what symbol is missing in the equation: </span><span>x 2-7x + 10, and I will help you solve it.</span>
So he started with 3/4 lb and ended up with 2/3 of that so 2/3 of 3/4
'of' can be roughly translated as multiply
so 2/3 times 3/4 =6/12=1/2 lb left
or you know that there are 3 out of 4 parts pound left so 2 out of 3 parts of nuts is = 2/4 or 1/2 lb
Answer:
x+2 x+2 x+2
Step-by-step explanation:
A suitable solver will tell you instantly that the measure of b is 179.18 ft.
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If you want to do it yourself (meaning also with the aid of a calculator), you can use the Law of Sines. The given side is side "c", so you need the measure of angle C. That will be
180° -33° -63° = 84°
Then side "b" can be found from
b/sin(B) = c/sin(C)
b = c*sin(B)/sin(C)
b = (200 ft)*sin(63°)/sin(84°) ≈ 179.183 ft
Explanation: The base of the power in the original equation becomes the base of the log. So we have 
. Next, the exponent in the original equation goes on the other side of the equation and finally, the result in the original equation goes inside the log.
So we have 
= 
which is 2³ = 8 written in logarithmic form.
