Mike drank more than half the juice in his glass. what fraction of the juice could Mike have drunk?
2 answers:
He drank more than half of his drink... So we need to look for fractions greater than 1/2.
First, lets find equivalents of 1/2
If all of these fractions are equal to 1/2, then by adding to the numerator of these fractions, we'l have fractions greater than 1/2.
2 +1 3
__= ___
4 4
3/4 is greater than 1/2
Mike could have drunken 3/4 of the juice
4/6>1/2 Mike could have drunken 4/6 of the juice
5/8 is greater then 1/2 Mike could have drank 5/8 of the drink.
Answer=3/4, 4/6, 5/8 and many more possible fractions
First, lets find equivalents of 1/2
If all of these fractions are equal to 1/2, then by adding to the numerator of these fractions, we'l have fractions greater than 1/2.
2 +1 3
__= ___
4 4
3/4 is greater than 1/2
Mike could have drunken 3/4 of the juice
4/6>1/2 Mike could have drunken 4/6 of the juice
5/8 is greater then 1/2 Mike could have drank 5/8 of the drink.
Answer=3/4, 4/6, 5/8 and many more possible fractions
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Answer:
a) (-5,0) and (1,0)
b) (0,-5)
c) minimum
See attached graph.
Step-by-step explanation:
To graph the function, find the vertex of the function find (-b/2a, f(-b/2a)). Substitute b = 4 and a = 1.
-4/2(1) = -4/2 = -2
f(-2) = (-2)^2 + 4(-2) - 5 = 4 - 8 - 5 = -4 - 5 = -9
Plot the point (-2,-9). Then two points two points on either side like x = -1 and x = -3. Substitute x = -1 and x = -3
f(-1) = (-1)^2 + 4 (-1) - 5 = 1 - 4 - 5 = -8
Plot the point (-1,-8).
f(-3) = (-3)^2 + 4(-3) - 5 = 9 - 12 - 5 = -8
Plot the point (-3,-8).
See the attached graph.
The features of the graph are:
a) (-5,0) and (1,0)
b) (0,-5)
c) minimum
