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3 years ago

HELP QUICK ME QUICK PLEASE THANKS

Mathematics

2 answers:

GenaCL600 [577]3 years ago

8 0

To solve this problem, we need to know the formula for the nth term of an arithmetic sequence. The formula is $a_{n}$ = t₁ + (n-1)d, with $a_{n}$ being the nth term, t₁ being the first term, and d being the distance between terms. Now we can substitute values to figure out what $a_{n}$ is. When substituting, the equation becomes:

$a_{n}$ = 12 + 29(-6)
$a_{n}$ = -162

That means that the 30th term in this arithmetic sequence is -162.

klemol [59]3 years ago

8 0

The answer would be D. -162

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The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is $14.28days^{-1}$

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

$m(t)=m_o(1/2)^{t/h}$

where,

m(t) = amount of sample after time 't' = 356 g

$m_o$ = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

$356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}$

Hence, the half life of the sample of phosphorus-32 is $14.28days^{-1}$

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Please see the picture below

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