You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
Answer:
0.04
Step-by-step explanation:
<span>This question requests to find the inverse function of sine function. The inverse function of sine function is called arc sine. This is, the arc length whose sine is the value searched. Then you need to find the arc sin (0.6123). the result may be in radians or degrees. Only in some particular cases you can tell the arc sine without a calculator or table, it is when the sine value is a notable number (e.g. 0, 1, -1, or some others) In this case you need to use a calculator or table. With a scientific calculator make sure the mode is in degrees and then enter the number 0.6123. With that numbered entered now press the key sin^-1, which is the key for the inverse of the sine function. I did it and got 37.76 degrees. Rounded to the nearest whole degree that is 38. Then, the answer is 38 degrees. </span>
Answer:
If AVC∠+CVB∠ it would be AVB∠ so I'm guessing it would AVC∠
Step-by-step explanation:
My knowledge ;)
<u>Answer:</u>
x = 2, x = -3
<u>Step-by-step explanation:</u>
We are given the following quadratic equation and we are to solve it for x:
We need to find such factors of -6 that when added give a result of 1 and when multiplied, give a product of -6.
x = 2, x = -3
