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3 years ago

What is the constat proportionlity in the equation 3y=2x

1 answer:

7 0

Answer:What is the proportionality constant in the 3y 2x equation? Since the equation can be written in the form y = kx y = k x, y varies directly with x and k. The variation constant k is 23.

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The number of chocolate chips in a popular brand of cookie is normally distributed with a mean of 22 chocolate chips per cookie

MA_775_DIABLO [31]

Answer:

The cutoff numbers for the number of chocolate chips in acceptable cookies are 16.242 and 27.758

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 22, \sigma = 3.5$

Middle 90%

Between the 50 - (90/2) = 5th percentile to the 50 + (90/2) = 95th percentile.

5th percentile:

X when Z has a pvalue of 0.05. So X when Z = -1.645.

$Z = \frac{X - \mu}{\sigma}$

$-1.645 = \frac{X - 22}{3.5}$

$X - 22 = -1.645*3.5$

$X = 16.242$

95th percentile:

X when Z has a pvalue of 0.95. So X when Z = 1.645.

$Z = \frac{X - \mu}{\sigma}$

$1.645 = \frac{X - 22}{3.5}$

$X - 22 = 1.645*3.5$

$X = 27.758$

The cutoff numbers for the number of chocolate chips in acceptable cookies are 16.242 and 27.758

3 0

3 years ago

Read 2 more answers

In AABC, BC = 6, CA = 14, and AB = 19. Which statement about the angles of AABC must be true?

zlopas [31]

Answer:

ca=14

Step-by-step explanation:

4 0

3 years ago

Tyler ate x fruit snacks, and Han ate less than that. Write an equation to represent the relationship between the number Tyler a

IRISSAK [1]

Tx -yx I believe not sure

6 0

3 years ago

G evaluate lim h → 0 (1 + h)9 − 1 h . hint: this limit represents the derivative of a function f at a given point

Bond [772]

$\displaystyle\lim_{h\to0}\frac{(1+h)^9-1}h$

Write $1=1^9$ , and recall that for a differentiable function $f(x)$ , the derivative at a point $x=a$ is given by

$f'(a)=\displaystyle\lim_{h\to0}\frac{f(a+h)-f(a)}h$

which would suggest that for this limit, $f(x)=x^9$ and $a=1$ . We have $f'(x)=9x^8$ , and so the value of the limit would be $9(1)^8=9$ .

7 0

3 years ago

-7/10+(-5/12)-(1/4)<br><br><br> Show work

patriot [66]

-41/30
Hope I didn't mess up

6 0

4 years ago