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Olenka [21]
3 years ago
13

Pls help me and i will know if it is wrong

Mathematics
1 answer:
DENIUS [597]3 years ago
8 0

9514 1404 393

Answer:

  90 miles

Step-by-step explanation:

Let d represent the distance to Grandma's house.

The speed going was ...

  speed = distance/time

  speed = d/2

The speed coming home was ...

  speed = d/2.25

The difference of these speeds is 5 miles per hour:

  d/2 -d/2.25 = 5

  2.25d -2d = 5(4.50) . . . . . multiply by 4.50

  0.25d = 22.5 . . . . . . . . . . .simplify

  d = 90 . . . . . . . . . . . . . . . . multiply by 4

Grandma's house is 90 miles away.

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A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the
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Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

25% of all adults had used the Internet for such a purpose

This means that \pi = 0.25

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

What is the required sample size for the new study?

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}

\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2

n = 800.3

Rounding up:

The required sample size for the new study is 801.

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Help pls- <br><br> I dont know it T^T
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Answer:

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Step-by-step explanation:

By the identity:

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