Question

Given that f(x) = 3x + 1 and g(x) = the quantity of 4x plus 2 divided by 3 , solve for g(f(0)). (5 points) 2 6 8 9

Answer 1

$f(0)=3(0)+1$

$f(0)=1$

$g(1)=\frac{4(1)+2}{3}$

$g(1)=\frac{4+2}{3}$

$g(1)=\frac{6}{3}$

$g(1)=2$

Hope this helps.

頑張って!