The architect earns $47000 yearly and the lawyer earns $68,000 yearly.
<h3>How to solve algebra problems?</h3>
Let x = salary of architect, in thousands
Let 2x - 26 be the salary of lawyer, in thousands
Thus, if their salary combined is $214 thousand, then we have the algebra expression;
2x + 2x - 26 = 214
4x - 26 = 214
4x = 214 - 26
4x = 188
x = 47, in thousands.
The architect earns $47000 yearly
The lawyer earns 2(47000) - 26000 = $68,000 yearly
Read more about Algebra Problems at; brainly.com/question/4344214
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Where/what slopes are I talking about?
Answer:
the answer is x=e⁴........
well, do a payments table of values, just like before for each mont hmm let's see
1st month.......................3500 + p(1)
2nd month....................3500 + p(2)
3rd month.....................3500 + p(3)
4th month.....................3500 + p(4)
5th month.....................3500 + p(5)
36th month..................3500 + p(36)
