All categories

3 years ago

Look at the picture. What is the solution WORTH 10 POINTS

Mathematics

1 answer:

Ivanshal [37]3 years ago

3 0

The coordinates of the point intersection of lines (-1, -1)

If you want solve:

y = -2x - 3, y = 3x + 2

-2x - 3 = 3x + 2 |+3

-2x = 3x + 5 |-3x

-5x = 5 |:(-5)

x = -1

Put the value of x to the first equation:

y = (-2)(-1) - 3 = 2 - 3 = -1

x = -1, y = -1

You might be interested in

Find the greatest common factor of the following monomials.<br> 25x^5 20x^6

klio [65]

1x25=25
5x5=25

1x20=20
2x10=20
4x5=20

x^5 is the biggest you can take out of x^5 and x^6 and 5 is the biggest number you can take out of 20 and 25

5m^5

8 0

2 years ago

Convert the following <br><br>250cm to m

dmitriy555 [2]

100 cm = 1m

1 cm = 1/100

250 cm = 1/100*250

= 2.5m

This is Right answer...

4 0

3 years ago

What are all the exact solutions of -3tan^2x+1= 0? Give your answer in radians

lord [1]

Answer:

x = π(n - $\frac{1}{6}$ )

Step-by-step explanation:

Find attached Solution

6 0

3 years ago

1. Write an equation in slope-intercept form for a line passing through (-3,3) with a slope of 1.

PIT_PIT [208]

$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{3})~\hspace{10em} slope = m\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-3=1[x-(-3)] \\\\\\ y-3=1(x+3)\implies y-3=x+3\implies y=x+6$

$\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-2}{1-(-4)}\implies \cfrac{10}{1+4}\implies \cfrac{10}{5}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=2[x-(-4)]\implies y-2=2(x+4) \\\\\\ y-2=2x+8\implies y=2x+10$

8 0

3 years ago

Lynomials and Linear Factors

kodGreya [7K]

Answer:

y = x³ + 2x² - 13x + 10

Step-by-step explanation:

Given

y = (x + 5)(x - 1)(x - 2) ← expand (x - 1)(x - 2)

= (x + 5)(x² - 2x - x + 2)

= (x + 5)(x² - 3x + 2)

Multiply each term in the second factor by each term in the first factor

= x(x² - 3x + 2) + 5(x² - 3x + 2) ← distribute both parenthesis

= x³ - 3x² + 2x + 5x² - 15x + 10 ← collect like terms

y = x³ + 2x² - 13x + 10

4 0

3 years ago