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3 years ago

Evaluate the expression for x=-6 4more than the product of-4 and the number

Mathematics

1 answer:

son4ous [18]3 years ago

8 0

Answer:

Step-by-step explanation:

The product of -4 and the unknown number n is -4n.

4 more than the product of -4 and the unknown number n is -4n + 4.

Letting n = -6 results in the value -4(-6) + 4, or 24 + 4, or 28.

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svetoff [14.1K]

If the length of the entire screwdriver is 19cm, and the handle is 5cm, subtract the length of the handle from the total length to find the length of the top of the screwdriver.
19 - 5 = 14
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3 years ago

Find the Area of the shape below.

kobusy [5.1K]

Answer:

42.5 Units squared

Step-by-step explanation:

Rectangle: 9.0 * 3.5 = 31.5

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3 years ago

In ΔDEF,{EF}\cong{DE} EF ≅ DE and m∠E = 104°. Find m∠D.

Alexeev081 [22]

The 3 inside angles need to equal 180.

Subtract E from 180 to find the sum of the other two angles:

180 - 104 = 76

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3 years ago

232 round to nearest ten

solniwko [45]

The nearst rounding to the tens is 230

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3 years ago

Read 2 more answers

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case

olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0

3 years ago

Read 2 more answers

Evaluate the expression for x=-6 4more than the product of-4 and the number ​

Evaluate the expression for x=-6 4more than the product of-4 and the number