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Anon25 [30]
2 years ago
12

Please help :3 Select EACH correct answer

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
4 0

You didn’t give the question

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According to the general equation for conditional probability, if P(A upside down u B)= 5/7 and P(B)=7/8 , what is P(A|B)?
natta225 [31]
P(A | B) = \frac{P(A \cap B)}{P(B)}


P(A|B) = \frac{5/7}{7/8}


P(A|B) = \frac{5}{7} \div \frac{7}{8}


P(A|B) = \frac{5}{7}\times\frac{8}{7}


P(A|B) = \frac{5*8}{7*7}


P(A|B) = \frac{40}{49}
7 0
3 years ago
The table shows the results of a random survey of kids between the ages of 10 and 15 about their favorite food.
Juliette [100K]
The exact number is 121.966019, so if you round to the nearest whole number, the answer is 122.
5 0
2 years ago
Please Help!!!
meriva
<span>3.9 - 0.234 = 3.666

Hope it helped
</span>
8 0
3 years ago
Read 2 more answers
Plz help and show work
scoundrel [369]

Answer:  If the 40% off coupon is used, the subtotal will be $12.69

The gratuity would be exactly $4.23   (He will probably leave $4.25)

Step-by-step explanation: To find out the amount  of the discount

.40 × 21.15 = 8.46

To find the new subtotal, subtract  12.15 - 8.46 = 12.69

To figure the tip:  .20 × 21.15 = 4.23

Changing the percent to a decimal means divide the 20 by 100.

8 0
3 years ago
Prove that u(n) is a group under the operation of multiplication modulo n.
katrin2010 [14]

Answer:

The answer is the proof so it is long.

The question doesn't define u(n), but it's not hard to guess.


Group G with operation ∘

For all a and b and c in G:

1) identity: e ∈ G, e∘a = a∘e = a,

2) inverse: a' ∈ G, a∘a' = a'∘a = e,

3) closed: a∘b ∈ G,

4) associative: (a∘b)∘c = a∘(b∘c),

5) (optional) commutative: a∘b = b∘a.


Define group u(n) for n prime is the set of integers 0 < i < n with operation multiplication modulo n.


If n isn't prime, we exclude from the group all integers which share factors with n.


Identity: e = 1. Clearly 1∘a = a∘1 = a. (a is already < n).


Closed: u(n) is closed for n prime. We must show that for all a, b ∈ u(n), the integer product ab is not divisible by n, so that ab ≢ 0 (mod n). Since n is prime, ab ≠ n. Since a < n, b < n, no factors of ab can equal prime n. (If n isn't prime, we already excluded from u(n) all integers sharing factors with n).


Inverse: for all a ∈ u(n), there is a' ∈ u(n) with a∘a' = 1. To find a', we apply Euclid's algorithm and write 1 as a linear combination of n and a. The coefficient of a is a' < n.


Associative and Commutative:

(a∘b)∘c = a∘(b∘c) because (ab)c = a(bc)

a∘b = b∘a because ab = ba.


5 0
2 years ago
Read 2 more answers
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