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Dmitriy789 [7]
2 years ago
9

Use all 4 operations and at least one exponent to write and expression that has a value of 10

Mathematics
1 answer:
Yuki888 [10]2 years ago
7 0

5+5=10

15-5=10

5x2=10

20/2=10

10^1 (10 to the power of 1) or 0.1^-1 (0.1 to the power of -1)

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200 stamps

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Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t
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Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

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3 years ago
Help Please!! I am not sure what to do?
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Answer:

10 < \sqrt{111} < 11

Step-by-step explanation:

The square root of 111 is approximately 10.536.

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A number larger than this is 11.

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Freee pointsss iggg :)
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Yayyy thanks a lottt can i also get brainliest
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