Let's solve this problem step-by-step.
−3(1−2x)=3x+3(x−3)+6
Step 1: Simplify both sides of the equation.
−3(1−2x)=3x+3(x−3)+6
(−3)(1)+(−3)(−2x)=3x+(3)(x)+(3)(−3)+6(Distribute)
−3+6x=3x+3x+−9+6
6x−3=(3x+3x)+(−9+6)(Combine Like Terms)
6x−3=6x+−3
6x−3=6x−3
Step 2: Subtract 6x from both sides.
6x−3−6x=6x−3−6x
−3=−3
Step 3: Add 3 to both sides.
−3+3=−3+3
0=0
So, 0=0 or all real numbers.
Answer:
Step-by-step explanation:
Line 1--------- >(0,2) (1,-1)
y=mx+b m=(-1-2)/(1-0)=-3
2=(-3)*(0)+b----- > b=2
y1=-3x+2Line 2--------- >(0,-1) (2,2)
y=mx+b m=(2+1)/(2-0)=3/2
-1=(3/2)*(0)+b----- > b=-1
y2=(3/2)x-1
<span>using a graphic tool
see attached figure</span>
the best estimate solution for the system is <span>
(1, 1)
because </span>is the only one within the range of the x axis (-5,5) and the y axis (-5,5)