Answer:
A) : p=0.5 (At least half of the workers are women,fair)
B) : p<0.5 (Less than half of the workers are women,unfair)
C) critical value of the test statistic is 1.64 (one tailed)
D) Test statistic is ≈ 0.29
E) Since 0.29<1.64, we fail to reject the null hypothesis. There is no significant evidence that the company has unfair hiring practices at 0.05 significance level.
Step-by-step explanation:
Let p be the proportion of women workers in the company. Null and alternative hypotheses are
: p=0.5 (At least half of the workers are women,fair)
: p<0.5 (Less than half of the workers are women,unfair)
Test statistic can be found using the equation:
z= where
- p(s) is the sample proportion of women workers (
)
- p is the proportion assumed under null hypothesis. (0.5)
- N is the sample size (55+52=107)
Then z= ≈ 0.29
For alpha 0.05, critical value of the test statistic is 1.64 (one tailed)
Since 0.29<1.64, we fail to reject the null hypothesis. There is no significant evidence that the company has unfair hiring practices at 0.05 significance level.
