Work out (5x10^3) x (5x10^7) standard form

1 answer:

3 0

5*10^3 * 5*10^7= 5*5 *10^3*10^7=25*10^10

Generally u are allowed to leave it as it is but if no

25*10^10=25 * 10000000000 = 250000000000

Here u are!

You might be interested in

Fourth degree and a single zero of -3

Darya [45]

The degree of a polynomial is the highest power of the polynomial.

The polynomial is $\mathbf{P(x) = (x + 3)^4}$

The degree is given as:

$\mathbf{n = 4}$

The zero is given as:

$\mathbf{x = -3}$

Add 3 to both sides

$\mathbf{x + 3= 0}$

From the question, we understand that the polynomial has a single zero.

So, the polynomial is:

$\mathbf{P(x) = (x + 3)^n}$

Substitute 4 for n

$\mathbf{P(x) = (x + 3)^4}$

Hence, the polynomial is $\mathbf{P(x) = (x + 3)^4}$

Read more about polynomials at:

brainly.com/question/11536910

3 0

3 years ago

You roll a 6-sided die.

Lerok [7]

Answer:

$\huge\boxed{\text{P(not factor of 35) = } \frac{2}{3}}$

Step-by-step explanation:

We can use basic probability to find the probability that this roll is not a factor of 35.

First off, we know that with a six sided die there are 6 possible things we can roll.

1, 2, 3, 4, 5, or 6

Now, what are the factors of 35? The factors of 35 will be any whole number that can be multiplied by another whole number to get 35.

We know $1 \cdot 35 = 35$ , so two factors are 1 and 35.
We know $5 \cdot 7 = 35$ , so two factors are 5 and 7.

Therefore, the factors of 35 are 1, 5, 7, 35.

Both 5 and 7 are inside the range of 1-6. So the probability of rolling a side that's a factor of 35 will be $\frac{2}{6} = \frac{1}{3}$ since there are two factors and 6 possible options.