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Bingel [31]
4 years ago
6

How many protons and electrons does 0^2- have?

Chemistry
1 answer:
Anestetic [448]4 years ago
5 0

Answer:

8 protons, 2 electrons

Explanation:

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Which of the following collisions will lead to the reaction shown above
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Atoms of which element below are most likely to gain electrons?
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Use the ΔHrxn values of the following reactions: 2SO2(g) + O2(g) → 2SO3(g) ΔHrxn = –196 kJ 2S(s) + 3O2(g) → 2SO3(g) ΔHrxn = –790
sesenic [268]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -297 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

S(s)+O_2(g)\rightarrow SO_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)    \Delta H_1=-196kJ

(2) 2S(g)+3O_2(g)\rightarrow 2SO_3(g)     \Delta H_2=-790kJ

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=\frac{[1\times (-\Delta H_1)]+[1\times \Delta H_2]}{2}

Putting values in above equation, we get:

\Delta H^o_{rxn}=\frac{[(1\times -(-196))+(1\times (-790))}{2}=-297kJ

Hence, the \Delta H^o_{rxn} for the reaction is -297 kJ.

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