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3 years ago

What are specatator ions

Chemistry

1 answer:

Margaret [11]3 years ago

5 0

Answer:

A spectator ion is an ion that does not participate in a chemical reaction and is found in a solution before and after a reaction.

Hope this helped :)

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A can of coke contains 25 mL of carbon dioxide gas at 100kPa. If you take it on a hike up Mount Everest and the pressure decreas

Mazyrski [523]

Answer:

50 mL

Explanation:

We can solve this problem by using Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

$p\propto \frac{1}{V}$

where

p is the pressure of the gas

V is the volume of the gas

The equation can be rewritten as

$p_1 V_1 = p_2 V_2$

where in this problem:

$p_1 = 100 kPa$ is the initial pressure of the gas in the coke

$V_1=25 mL$ is the initial volume

$p_2=50 kPa$ is the final pressure

Solving for V2, we find the final volume:

$V_2=\frac{p_1 V_1}{p_2}=\frac{(100)(25)}{50}=50 mL$

7 0

4 years ago

The molar solubilities of the following compounds (in mol/L) are:

IceJOKER [234]

Answer: The decreasing order of $K_{sp}$ is $AgSCN>AgBr>AgCN$

Explanation:

For AgBr:

The balanced equilibrium reaction for the ionization of silver bromide follows:

$AgBr\rightleftharpoons Ag^{+}+Br^-$

s s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Ag^{+}][Br^-]$

We are given:

$s=7.3\times 10^{-7}mol/L$

Putting values in above equation, we get:

$K_{sp}=s\times s\\\\K_{sp}=s^2\\\\K_{sp}=(7.3\times 10{-7})^2=5.33\times 10^{-13}$

Solubility product of AgBr = $5.33\times 10^{-13}$

For AgCN:

The balanced equilibrium reaction for the ionization of silver cyanide follows:

$AgCN\rightleftharpoons Ag^{+}+CN^-$

s s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Ag^{+}][CN^-]$

We are given:

$s=7.7\times 10^{-9}mol/L$

Putting values in above equation, we get:

$K_{sp}=s\times s\\\\K_{sp}=s^2\\\\K_{sp}=(7.7\times 10{-9})^2=5.93\times 10^{-17}$

Solubility product of AgCN = $5.33\times 10^{-17}$

For AgSCN:

The balanced equilibrium reaction for the ionization of silver thiocyanate follows:

$AgSCN\rightleftharpoons Ag^{+}+SCN^-$

s s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Ag^{+}][SCN^-]$

We are given:

$s=1.0\times 10^{-6}mol/L$

Putting values in above equation, we get:

$K_{sp}=s\times s\\\\K_{sp}=s^2\\\\K_{sp}=(1.0\times 10{-6})^2=1.0\times 10^{-12}$

Solubility product of AgSCN = $1.0\times 10^{-12}$

The decreasing order of $K_{sp}$ follows:

$AgSCN>AgBr>AgCN$

4 0

4 years ago

What would happen to a plant if it´s chloroplasts stopped working?

slava [35]

Answer: Basically plants wouldn't be able to preform photosynthesis and they would die

Explanation:

8 0

3 years ago

Read 2 more answers

Please help with the last problem!

CaHeK987 [17]

Radiation: Heat from the stovetop.
Conduction: Heat from Stove to Pot.
Convection: Water boiling.
I will now take my points.

8 0

3 years ago

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What activity best demonstrates the use of creativity of j.j. thomson's work

seropon [69]

The plum pudding model of the atom by the scientist Sir Joseph John Thompson or J.J. Thompson. It was theorized after the discovery that electrons are present in the atom. In this model, the atom is composed mainly of electrons. It was describe as plum pudding because the electrons are dispersed within the atom. John Dalton discovered the atom. Ernest Rutherford discovered the half – life of an atom and Neils Bohr explain the quantum mechanics. So the answer is J.J. Thompson.

7 0

3 years ago