First we need to find the number of moles of hydrogen gas formed
Zn + 2HCl ---> ZnCl₂ + H₂
stoichiometry of Zn to H₂ is 1:1
the number of Zn moles reacted - 2.4 g / 65.4 g/mol = 0.0367 mol
assuming Zn to be the limiting reactant
number of Zn moles reacted = number of H₂ moles formed
therefore number of H₂ moles formed = 0.0367 mol
we can use ideal gas law equation to find the pressure
PV = nRT
P - pressure
V - Volume - 450 x 10⁻⁶ m³
n - number of moles - 0.0367 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 32 °C + 273 = 305 K
substituting these values in the equation
P x 450 x 10⁻⁶ m³ = 0.0367 mol x 8.314 Jmol⁻¹K⁻¹ x 305 K
P = 206.8 kPa
pressure is 206.8 kPa
Answer:
CH2
Explanation:
We are given that a compound is 14.40% hydrogen and 85.60% carbon.
Let the mass of the substance be 100g.
Mass of the hydrogen: 14.40% of 100 = 14.40 g
Mass of the carbon: 85.60% of 100 = 85.60 g
Now, let's find the moles of hydrogen:
Moles of carbon:
Let's put these in a ratio and simplify:
7.13 mole C: 14.40 mole H
1 mole C: 2 mole H
Therefore, the empirical formula of this compound is CH2.
Hope this helps!! If you have any questions about my work, please let me know in the comments!
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