Answer:
a. p(orange) = 5/14
b. p(green) = 3/14
c. p(red) = 1/7
d. p(brown) = 2/7
e. p(brown or red) = 3/7
Step-by-step explanation:
1. You have a 14 pencils. Two pencils are red, 5 pencils are orange, 3 pencils are green and 4 pencils are brown.
p(color) = (number of pencils of that color)/(total number of pencils)
p(color) = (number of pencils of that color)/14
a. If a pencil is picked at random, what is the probability that the pencil
will be orange?
p(orange) = 5/14
b. If a pencil is picked at random, what is the probability that the pencil
will be green?
p(green) = 3/14
c. If a pencil is picked at random, what is the probability that the pencil will be red?
p(red) = 2/14 = 1/7
d. If a pencil is picked at random, what is the probability that the pencil
will be brown?
p(brown) = 4/14 = 2/7
e. If a pencil is picked at random, what is the probability that the pencil
will be brown or red?
brown: 4
red: 2
brown or red: 4 + 2
p(brown or red) = 6/14 = 3/7
Answer:
Step-by-step explanation:
Reduction to normal from using lambda-reduction:
The given lambda - calculus terms is, (λf. λx. f (f x)) (λy. Y * 3) 2
For the term, (λy. Y * 3) 2, we can substitute the value to the function.
Therefore, applying beta- reduction on "(λy. Y * 3) 2" will return 2*3= 6
So the term becomes,(λf. λx. f (f x)) 6
The first term, (λf. λx. f (f x)) takes a function and an argument, and substitute the argument in the function.
Here it is given that it is possible to substitute the resulting multiplication in the result.
Therefore by applying next level beta - reduction, the term becomes f(f(f(6)) (f x)) which is in normal form.
B, make a table of possible values
the best way to do it is actually not listed
to have max area with minimu perimiter, try to get the sides as close measure to each other as possible
I would pick B though
Answer:
C) y = 2.50x + 10
Step-by-step explanation:
Equation C is saying:
total cost = 2.50(number of games) + $10 entery fee
Hope this helps :)
In order to solve that, let's call 845 100%, as we're solving it terms of 845. 845 is 100%, then it follows that 8.45 is 1%.
Now we can see how many 8.45's go into 608, which comes out to 71.95266...%, which can be rounded nicely to 72%
The million doesn't matter.
